(x-5)^2/3=125

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Solution for (x-5)^2/3=125 equation:


x in (-oo:+oo)

((x-5)^2)/3 = 125 // - 125

((x-5)^2)/3-125 = 0

((x-5)^2)/3+(-125*3)/3 = 0

(x-5)^2-125*3 = 0

x^2-10*x-350 = 0

x^2-10*x-350 = 0

x^2-10*x-350 = 0

DELTA = (-10)^2-(-350*1*4)

DELTA = 1500

DELTA > 0

x = (1500^(1/2)+10)/(1*2) or x = (10-1500^(1/2))/(1*2)

x = (10*15^(1/2)+10)/2 or x = (10-10*15^(1/2))/2

(x-((10-10*15^(1/2))/2))*(x-((10*15^(1/2)+10)/2)) = 0

((x-((10-10*15^(1/2))/2))*(x-((10*15^(1/2)+10)/2)))/3 = 0

((x-((10-10*15^(1/2))/2))*(x-((10*15^(1/2)+10)/2)))/3 = 0 // * 3

(x-((10-10*15^(1/2))/2))*(x-((10*15^(1/2)+10)/2)) = 0

( x-((10*15^(1/2)+10)/2) )

x-((10*15^(1/2)+10)/2) = 0 // + (10*15^(1/2)+10)/2

x = (10*15^(1/2)+10)/2

( x-((10-10*15^(1/2))/2) )

x-((10-10*15^(1/2))/2) = 0 // + (10-10*15^(1/2))/2

x = (10-10*15^(1/2))/2

x in { (10*15^(1/2)+10)/2, (10-10*15^(1/2))/2 }

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